JEE Main 2019ChemistryRedox ReactionsEasyMCQ

JEE Main 2019Redox Reactions Question with Solution

JEE Main 2019 (08 Apr Shift 1)

Question

Given that,

EO2/H2Oo=+1.23 V;
ES2O82-/SO42-o=2.05 V
EBr2/Br-o=+1.09 V;
EAu3+/Auo=1.4 V


The strongest oxidizing agent is

Choose an option

Show full solutionCorrect option: B
Correct answer
B S2O82-

Step-by-step explanation

For strongest oxidizing agent, the standard reduction potential should be highest.

An oxidizing agent, or oxidising agent is a substance that has the ability to oxidize other substances — in other words to accept their electrons. Common oxidizing agents are oxygen, hydrogen peroxide and the halogens.

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About this question

This is a previous-year question from JEE Main 2019, covering the Redox Reactions chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.