JEE Main 2020ChemistryRedox ReactionsEasyMCQ

JEE Main 2020 — Redox Reactions Question with Solution

JEE Main 2020 (07 Jan Shift 1)

Question

Oxidation number of potassium in K2O,K2O2 and KO2, respectively, is:

Choose an option

Show full solutionCorrect option: B
Correct answer
B+1,+1 and +1

Step-by-step explanation

K 2 O    K +1 − O −2 − K +1 oxygen is more E.N. than potassium

K 2O 2     K +1 − O −1 − O −1 − K +1

  K O 2

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Redox Reactions chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2020, covering the Redox Reactions chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.