JEE Main 2023ChemistryRedox ReactionsMediumNumerical

JEE Main 2023 — Redox Reactions Question with Solution

JEE Main 2023 (25 Jan Shift 1)

Question

The density of a monobasic strong acid (Molar mass 24.2 g mol) is 1.21 kg L. The volume of its solution required for the complete neutralization of 25 mL of 0.24 M NaOH is 10-2 mL (Nearest integer)

Enter your answer

Show full solutionCorrect answer: 12
Correct answer
12

Step-by-step explanation

millimole of NaOH=0.24×25
For nuetralisation, equal moles of monoacidic base and monobasic acid must be present:

∴ millimole of acid =0.24×25

⇒ mass of acid =0.24×25×24.2 g

for pure acid,

V=wd;(d=1.21 kg/L=1.21 g/ml)

∴V=0.24×25×24.21.12×10-3

=120×10-3ml

=12×10-2ml

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Redox Reactions chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2023, covering the Redox Reactions chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.