JEE Main 2023ChemistrySolid StateHardNumerical

JEE Main 2023 — Solid State Question with Solution

JEE Main 2023 (11 Apr Shift 1)

Question

An atomic substance A of molar mass 12 g mol–1 has a cubic crystal structure with edge length of 300 pm. The no. of atoms present in one unit cell of A is

(Nearest integer)

Given the density of A is 3.0 g m m-1 and NAA=6.02×1023 mol-1

Enter your answer

Show full solutionCorrect answer: 4
Correct answer
4

Step-by-step explanation

The density of crystal can be calculated as follows,

ρ=Z×MNA×a3

ρ=density of the unit cell

Z=Effective atomic number

M=Molar mass

NA=Avogadro's number

a=Edge length of the unit cell

3=Z×126.02×1023×(3)3×10-24

Z=6.02×10-1×274=4

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About this question

This is a previous-year question from JEE Main 2023, covering the Solid State chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.