JEE Main 2020 — Solid State Question with Solution
From: JEE Main 2020 (Online) 5th September Morning Slot
Question
A diatomic molecule X2
has a body-centred cubic
(bcc) structure with a cell edge of 300 pm. The
density of the molecule is 6.17 g cm–3. The number
of molecules present in 200 g of X2
is :
(Avogadro constant (N A) = 6 1023 mol–1 )
(Avogadro constant (N A) = 6 1023 mol–1 )
Choose an option
Show full solutionCorrect option: C
Correct answer
C4 NA
Step-by-step explanation
d =
6.17 = [For BCC Z = 2]
M = 50 g/mol
Number of moles in 200 gm = = 4
Number of molecules = 4NA
6.17 = [For BCC Z = 2]
M = 50 g/mol
Number of moles in 200 gm = = 4
Number of molecules = 4NA
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