JEE Main 2021 — Solutions Question with Solution
From: JEE Main 2021 (Online) 25th July Morning Shift
Question
CO2 gas is bubbled through water during a soft drink manufacturing process at 298 K. If CO2 exerts a partial pressure of 0.835 bar then x m mol of CO2 would dissolve in 0.9 L of water. The value of x is ____________. (Nearest integer)
(Henry's law constant for CO2 at 298 K is 1.67 103 bar)
(Henry's law constant for CO2 at 298 K is 1.67 103 bar)
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Show full solutionCorrect answer: 25
Correct answer
25
Step-by-step explanation
From Henry's law
Pgas = KH.Xgas
0.835 = 1.67 103
n(CO2) = 0.025
Millimoles of CO2 = 0.025 1000 = 25
Pgas = KH.Xgas
0.835 = 1.67 103
n(CO2) = 0.025
Millimoles of CO2 = 0.025 1000 = 25
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