JEE Main 2021 — Solutions Question with Solution
From: JEE Main 2021 (Online) 25th July Evening Shift
Question
When 3.00 g of a substance 'X' is dissolved in 100 g of CCl4, it raises the boiling point by 0.60 K. The molar mass of the substance 'X' is ______________ g mol1. (Nearest integer).
[Given Kb for CCl4 is 5.0 K kg mol1]
[Given Kb for CCl4 is 5.0 K kg mol1]
Enter your answer
Show full solutionCorrect answer: 250
Correct answer
250
Step-by-step explanation
Tb = Kb molality
0.60 = 5
M = 250
0.60 = 5
M = 250
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This is a previous-year question from JEE Main 2021, covering the Solutions chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.