JEE Main 2021 — Solutions Question with Solution
From: JEE Main 2021 (Online) 31st August Evening Shift
Question
1.22 g of an organic acid is separately dissolved in 100 g of benzene (Kb = 2.6 K kg mol1) and 100 g of acetone (Kb = 1.7 K kg mol1). The acid is known to dimerize in benzene but remain as a monomer in acetone. The boiling point of the solution in acetone increases by 0.17C. The increase in boiling point of solution in benzene in C is x 102. The value of x is ______________. (Nearest integer) [Atomic mass : C = 12.0, H = 1.0, O =16.0]
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Show full solutionCorrect answer: 13
Correct answer
13
Step-by-step explanation
With benzene as solvent
Tb = i Kb m
Tb = 2.6 .... (1)
With Acetone as solvent
Tb = i Kb m
0.17 = 1 1.7 ..... (2)
(1) / (2)
Tb =
Tb = 13 102
x = 13
Tb = i Kb m
Tb = 2.6 .... (1)
With Acetone as solvent
Tb = i Kb m
0.17 = 1 1.7 ..... (2)
(1) / (2)
Tb =
Tb = 13 102
x = 13
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This is a previous-year question from JEE Main 2021, covering the Solutions chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.