JEE Main 2026 — Solutions Question with Solution
JEE Main 2026 (24 January Shift 2)
Question
At 298 K, the mole percentage of in air is . Water is in equilibrium with air at a pressure of 10 atm. What is the mole fraction of in water at 298 K ? ( for is )
Choose an option
Show full solutionCorrect option: D
Correct answer
D
Step-by-step explanation
Using Henry's Law: Mole fraction =
N₂ mole percentage in air = 80%, total pressure = 10 atm
Partial pressure of N₂ = 0.80 × 10 = 8 atm = 8 × 760 = 6080 mmHg
for N₂ = 6.5 × 10⁷ mmHg
Mole fraction of N₂ =
N₂ mole percentage in air = 80%, total pressure = 10 atm
Partial pressure of N₂ = 0.80 × 10 = 8 atm = 8 × 760 = 6080 mmHg
for N₂ = 6.5 × 10⁷ mmHg
Mole fraction of N₂ =
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