JEE Main 2019ChemistrySolutionsHenrys LawmediumMCQ

JEE Main 2019Solutions Question with Solution

From: JEE Main 2019 (Online) 8th April Evening Slot

Question

For the solution of the gases w, x, y and z in water at 298K, the Henrys law constants (KH) are 0.5, 2, 35 and 40 kbar, respectively. The correct plot for the given data is :-

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Correct answer
AJEE Main 2019 (Online) 8th April Evening Slot Chemistry - Solutions Question 127 English Option 1

Step-by-step explanation

Henry's law expression,

Pgas = KH xgas

Here, Pgas = partial pressure of gas

KH = Henry’s law constant

xgas = mole fraction of gas

xgas = 1 - xH2O

Pgas = KH (1 - xH2O)

Pgas = KH - KH xH2O

By comparing this equation with y = mx + c,

c = KH = Intercept

m = - KH = slope

So in partial pressure vs mole fraction of water graph, which gas has more KH will have more intercept. Given (KH) are 0.5, 2, 35 and 40 kbar for w, x, y, z respectively. So intercept of z should be the most and should be the least.

As solpe is = - KH, so slope shoul be negative for all the gases and w gas should have least negative slope and z should have highest negative slope.

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About this question

This is a previous-year question from JEE Main 2019, covering the Solutions chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.