JEE Main 2020 — Solutions Question with Solution
From: JEE Main 2020 (Online) 3rd September Morning Slot
Question
Henry’s constant (in kbar) for four gases , , and in water at 298 K is given below :
(density of water = 103 kg m-3 at 298 K)
This table implies that :
| KH | 50 | 2 | 2 10-5 | 0.5 |
(density of water = 103 kg m-3 at 298 K)
This table implies that :
Choose an option
Show full solutionCorrect option: A
Correct answer
Asolubility of at 308 K is lower than at 298 K
Step-by-step explanation
(1) On increasing temperature solubility of gases decreases.
(2) 55.5 molal solution of = 55.5 mol of
P = KHX
= 2 10-5
= 10–5 K bar
= 10–2 bar
(3) P = KHX
= 0.5
= 250 bar
(4) With temperature, the value of KH (Henry’s constant) increases and solubility of gas in liquid decreases.
(2) 55.5 molal solution of = 55.5 mol of
P = KHX
= 2 10-5
= 10–5 K bar
= 10–2 bar
(3) P = KHX
= 0.5
= 250 bar
(4) With temperature, the value of KH (Henry’s constant) increases and solubility of gas in liquid decreases.
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This is a previous-year question from JEE Main 2020, covering the Solutions chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.