JEE Main 2021 — Some Basic Concepts Of Chemistry Question with Solution
From: JEE Main 2021 (Online) 20th July Morning Shift
Question
An average person needs about 10000 kJ energy per day. The amount of glucose (molar mass = 180.0 g mol1) needed to meet this energy requirement is ____________ g.
(Use : CH(glucose) = 2700 kJ mol1)
(Use : CH(glucose) = 2700 kJ mol1)
Enter your answer
Show full solutionCorrect answer: 666.666
Correct answer
666.666
Step-by-step explanation
1 mole glucose give 2700 kJ energy,
so mole of glucose needed for 104 kJ energy
= moles
Weight of glucose = 3.703 180 g/moles
= 666.666
667 g
Hence, amount of glucose required is 667 g.
so mole of glucose needed for 104 kJ energy
= moles
Weight of glucose = 3.703 180 g/moles
= 666.666
667 g
Hence, amount of glucose required is 667 g.
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