JEE Main 2021 — Some Basic Concepts Of Chemistry Question with Solution
From: JEE Main 2021 (Online) 25th July Morning Shift
Question
When 10 mL of an aqueous solution of Fe2+ ions was titrated in the presence of dil H2SO4 using diphenylamine indicator, 15 mL of 0.02 M solution of K2Cr2O7 was required to get the end point. The molarity of the solution containing Fe2+ ions is x 102 M. The value of x is __________. (Nearest integer)
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Show full solutionCorrect answer: 18
Correct answer
18
Step-by-step explanation
milli-equivalents of Fe2+ = milli-equivalents of K2Cr2O7
M 10 1 = 0.02 15 6
M = 0.18 = 18 102 M
M 10 1 = 0.02 15 6
M = 0.18 = 18 102 M
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This is a previous-year question from JEE Main 2021, covering the Some Basic Concepts Of Chemistry chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.