JEE Main 2021 — Some Basic Concepts Of Chemistry Question with Solution
From: JEE Main 2021 (Online) 27th August Evening Shift
Question
100 g of propane is completely reacted with 1000 g of oxygen. The mole fraction of carbon dioxide in the resulting mixture is x 102. The value of x is ____________. (Nearest integer)
[Atomic weight : H = 1.008; C = 12.00; O = 16.00]
[Atomic weight : H = 1.008; C = 12.00; O = 16.00]
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Show full solutionCorrect answer: 19.02
Correct answer
19.02
Step-by-step explanation
C3H8(g) + 5O2(g) 3CO2(g) + 4H2O(l)
mole fraction of CO2 in the final reaction mixture (heterogenous)
= 0.1902 = 19.02 102
19
| t = 0 | 2.27 mole | 31.25 mol | ||
|---|---|---|---|---|
| t = | 0 | 19.9 mol | 6.81 mol | 9.08 mol |
mole fraction of CO2 in the final reaction mixture (heterogenous)
= 0.1902 = 19.02 102
19
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