JEE Main 2021 — Some Basic Concepts Of Chemistry Question with Solution
From: JEE Main 2021 (Online) 1st September Evening Shift
Question
If 80 g of copper sulphate CuSO4 . 5H2O is dissolved in deionised water to make 5L of solution. The concentration of the copper sulphate solution is x 103 mol L1. The value of x is _____________.
[Atomic masses Cu : 63.54u, S : 32u, O : 16u, H : 1u]
[Atomic masses Cu : 63.54u, S : 32u, O : 16u, H : 1u]
Enter your answer
Show full solutionCorrect answer: 64.11
Correct answer
64.11
Step-by-step explanation
Given, mass of CuSO4 . 5H2O = 80 g
The concentration of copper sulphate solution is x 103 mol/L.
Molarity = ..... (i)
Molar mass of CuSO4 . 5H2O = 63.54 + 32 + 16 4
= 5 18 = 249.54 g/mol
Number of moles of solute =
= = 0.32 mol
Volume of solution = 5 L
From Eq. (i),
Molarity = = 64.11 103 mol/L
x = 64.11
or x 64
Hence, answer is 64.
The concentration of copper sulphate solution is x 103 mol/L.
Molarity = ..... (i)
Molar mass of CuSO4 . 5H2O = 63.54 + 32 + 16 4
= 5 18 = 249.54 g/mol
Number of moles of solute =
= = 0.32 mol
Volume of solution = 5 L
From Eq. (i),
Molarity = = 64.11 103 mol/L
x = 64.11
or x 64
Hence, answer is 64.
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