JEE Main 2026 — Some Basic Concepts of Chemistry Question with Solution
JEE Main 2026 (21 January Shift 1)
Question
80 mL of a hydrocarbon on mixing with 264 mL of oxygen in a closed U-tube undergoes complete combustion. The residual gases after cooling to 273 K occupy 224 mL. When the system is treated with KOH solution, the volume decreases to 64 mL. The formula of the hydrocarbon is :
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Show full solutionCorrect option: A
Correct answer
A
Step-by-step explanation
KOH absorbs . Volume of produced = mL
Unreacted mL, so consumed = mL
For hydrocarbon :
consumed per mole =
Hydrocarbon is
Unreacted mL, so consumed = mL
For hydrocarbon :
consumed per mole =
Hydrocarbon is
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This is a previous-year question from JEE Main 2026, covering the Some Basic Concepts of Chemistry chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.