JEE Main 2017 — Some Basic Concepts Of Chemistry Question with Solution
From: JEE Main 2017 (Offline)
Question
1 gram of a carbonate (M2CO3) on treatment with excess HCl produces 0.01186 mole of CO2. The molar mass of M2CO3 in g mol–1 is:
Choose an option
Show full solutionCorrect option: A
Correct answer
A84.3
Step-by-step explanation
M2CO3 + 2HCl 2MCl + CO2 + H2O
Here weight of M2CO3 = 1 gm
Let molar mass of M2CO3 = M
No of moles of M2CO3 =
For this reaction,
= = 84.3 g mol-1
NOTE :
For any reaction this will be always valid.
For this reaction, 2KClO3 2KCl + 3O2
We can write,
This means
Here weight of M2CO3 = 1 gm
Let molar mass of M2CO3 = M
No of moles of M2CO3 =
For this reaction,
= = 84.3 g mol-1
NOTE :
For any reaction this will be always valid.
For this reaction, 2KClO3 2KCl + 3O2
We can write,
This means
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This is a previous-year question from JEE Main 2017, covering the Some Basic Concepts Of Chemistry chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.