JEE Main 2018 — Some Basic Concepts Of Chemistry Question with Solution
From: JEE Main 2018 (Online) 16th April Morning Slot
Question
An unknown chlorohydrocarbon has 3.55% of chlorine. If each molecule of the hydrocarbon has one chlorine atom only; chlorine atoms present in 1 g of chlorohydrocarbon are :
(Atomic wt. of Cl = 35.5 u; Avogadro constant = 6.023 1023 mol-1)
(Atomic wt. of Cl = 35.5 u; Avogadro constant = 6.023 1023 mol-1)
Choose an option
Show full solutionCorrect option: A
Correct answer
A6.023 1020
Step-by-step explanation
% of Cl = 3.55
In 100 g chlorohydrocarbon 3.55 gm Cl present.
In 1 gm chlorohydrocarbon Cl present
=
= 0.0355 gm
No of Moles of Cl =
= 0.001 mole
no of Cl atoms = 0.001 6.023 103
= 6.023 1020
In 100 g chlorohydrocarbon 3.55 gm Cl present.
In 1 gm chlorohydrocarbon Cl present
=
= 0.0355 gm
No of Moles of Cl =
= 0.001 mole
no of Cl atoms = 0.001 6.023 103
= 6.023 1020
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