JEE Main 2020 — Some Basic Concepts Of Chemistry Question with Solution
From: JEE Main 2020 (Online) 8th January Morning Slot
Question
Ferrous sulphate heptahydrate is used to fortify foods with iron. The amount (in grams) of the salt required to
achieve 10 ppm of iron in 100 kg of wheat is _______.
Atomic weight : Fe = 55.85; S = 32.00; O = 16.00
Atomic weight : Fe = 55.85; S = 32.00; O = 16.00
Enter your answer
Show full solutionCorrect answer: 4.97
Correct answer
4.97
Step-by-step explanation
FeSO4.7H2O (M = 277.85)
PPM =
10 =
Mass of Iron = 1 gm
Molecular mass of FeSO4.7H2O is 277.85
55.85 gm iron is present in 277.85 gm of salt
1 gm iron is present in = = 4.97 gm of salt.
PPM =
Mass of Iron
Mass of wheat
106
10 =
Mass of Iron
100 103
106
Mass of Iron = 1 gm
Molecular mass of FeSO4.7H2O is 277.85
55.85 gm iron is present in 277.85 gm of salt
1 gm iron is present in = = 4.97 gm of salt.
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