JEE Main 2004 — Some Basic Concepts Of Chemistry Question with Solution
From: AIEEE 2004
Question
To neutralise completely 20 mL of 0.1 M aqueous solution of phosphorous acid (H3PO3), the volume of 0.1 M aqueous KOH solution required is
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Show full solutionCorrect option: A
Correct answer
A40 mL
Step-by-step explanation
H3PO3 + 2KOH K2HPO3 + 2H2O
Let the volume of KOH solution is = V mL = litre
Volume of H3PO3 = 20 mL = litre
No of moles of H3PO3 present =
No of moles of KOH present =
Stoichiometric coefficient of H3PO3 = 1
Stoichiometric coefficient of KOH = 2
=
V = 40 mL
Let the volume of KOH solution is = V mL = litre
Volume of H3PO3 = 20 mL = litre
No of moles of H3PO3 present =
No of moles of KOH present =
Stoichiometric coefficient of H3PO3 = 1
Stoichiometric coefficient of KOH = 2
=
V = 40 mL
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This is a previous-year question from JEE Main 2004, covering the Some Basic Concepts Of Chemistry chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.