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JEE Main 2021 — Some Basic Concepts Of Chemistry Question with Solution

From: JEE Main 2021 (Online) 16th March Evening Shift

Question

When 35 mL of 0.15 M lead nitrate solution is mixed with 20 mL of 0.12 M chromic sulphate solution, _________ 105 moles of lead sulphate precipitate out. (Round off to the Nearest Integer).

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Show full solutionCorrect answer: 525
Correct answer
525

Step-by-step explanation

JEE Main 2021 (Online) 16th March Evening Shift Chemistry - Some Basic Concepts of Chemistry Question 151 English Explanation 1

For 3 moles of Pb(NO3)2 , we require 1 mole of Cr2(SO4)3

For 5.25 moles of Pb(NO3)2, we require mole of Cr2(SO4)3 = 1.75 moles

But we have 2.4 moles. So, Cr2(SO4)3 is excess reagent and Pb(NO3)2 is limiting reagent, (LR)

JEE Main 2021 (Online) 16th March Evening Shift Chemistry - Some Basic Concepts of Chemistry Question 151 English Explanation 2

Moles of PbSO4 formed = moles of Pb(NO3)2 consumed

= 5.25 m mol = 525 10-5 moles

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About this question

This is a previous-year question from JEE Main 2021, covering the Some Basic Concepts Of Chemistry chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.