JEE Main 2018 — Some Basic Concepts Of Chemistry Question with Solution
From: JEE Main 2018 (Online) 15th April Morning Slot
Question
A sample of is converted by heat to with a loss of of oxygen. The residue is dissolved in water and precipitated as The mass of (in ) obtained will be : (Given : Molar mass of )
Choose an option
Show full solutionCorrect option: C
Correct answer
C
Step-by-step explanation
NaClO3 2NaCl + 3O2
Here O2 produced = 0.16 g
No of moles of O2 = = 5 103
Let no of moles of NaCl
=
= 5 103 =
NaCl + Ag+ AgCl + Na+
From here, you can see
no of moles in NaCl = no of moles in AgCl
no of moles in AgCl =
Mass of AgCl = 143.5 = 0.48 g
Here O2 produced = 0.16 g
No of moles of O2 = = 5 103
Let no of moles of NaCl
=
= 5 103 =
NaCl + Ag+ AgCl + Na+
From here, you can see
no of moles in NaCl = no of moles in AgCl
no of moles in AgCl =
Mass of AgCl = 143.5 = 0.48 g
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This is a previous-year question from JEE Main 2018, covering the Some Basic Concepts Of Chemistry chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.