JEE Main 2019 — Some Basic Concepts Of Chemistry Question with Solution
From: JEE Main 2019 (Online) 12th January Evening Slot
Question
8 g of NaOH is dissolved in 18g of H2O. Mole fraction of NaOH in solution and molality (in mol kg–1) of the solution respectively are -
Choose an option
Show full solutionCorrect option: C
Correct answer
C0.167, 11.11
Step-by-step explanation
8 gm of NaOH = = 0.2 mol of NaOH
18 gm of H2O = = 1 mol of H2O
Total mole = 1 + 0.2 = 1.2 mol
Mole fraction of NaOH = = 0.167
We know,
Molality = 1000
= 1000
= 11.11
18 gm of H2O = = 1 mol of H2O
Total mole = 1 + 0.2 = 1.2 mol
Mole fraction of NaOH = = 0.167
We know,
Molality = 1000
= 1000
= 11.11
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