JEE Main 2012 — Some Basic Concepts Of Chemistry Question with Solution
From: AIEEE 2012
Question
The density of a solution prepared by dissolving 120 g of urea (mol. Mass = 60 u ) in 1000g of water is
1.15 g/mL. The molarity of this solution is :
Choose an option
Show full solutionCorrect option: D
Correct answer
D2.05 M
Step-by-step explanation
We know molarity (M) =
Moles of solute = = 2
Mass of solution = 1000 + 120 = 1120 gm
Density of solution = 1.15 g/mL
volume of solution = = 973.9 mL = litre = 0.9739 litre
M = = 2.05
Moles of solute = = 2
Mass of solution = 1000 + 120 = 1120 gm
Density of solution = 1.15 g/mL
volume of solution = = 973.9 mL = litre = 0.9739 litre
M = = 2.05
Practice this on the real CBT interface
Solve this JEE Main question (and the rest of the Some Basic Concepts Of Chemistry chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.
Solve interactively →About this question
This is a previous-year question from JEE Main 2012, covering the Some Basic Concepts Of Chemistry chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.