JEE Main 2019 — Some Basic Concepts Of Chemistry Question with Solution
From: JEE Main 2019 (Online) 10th January Evening Slot
Question
The amount of sugar (C12H22O11) required to prepare 2L of its 0.1 M aqueous solution is :
Choose an option
Show full solutionCorrect option: C
Correct answer
C68.4 g
Step-by-step explanation
Molarity =
0.1 =
wt (C12H22O11) = 68.4 gram
0.1 =
wt (C12H22O11) = 68.4 gram
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This is a previous-year question from JEE Main 2019, covering the Some Basic Concepts Of Chemistry chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.