JEE Main 2019 — Some Basic Concepts Of Chemistry Question with Solution
From: JEE Main 2019 (Online) 9th April Morning Slot
Question
For a reaction,
N2(g) + 3H2(g) 2NH3(g) ;
identify dihydrogen (H2) as a limiting reagent in the following reaction mixtures.
N2(g) + 3H2(g) 2NH3(g) ;
identify dihydrogen (H2) as a limiting reagent in the following reaction mixtures.
Choose an option
Show full solutionCorrect option: A
Correct answer
A56g of N2 + 10g of H2
Step-by-step explanation
Here you have to check every options to find answer.
N2(g) + 3H2(g) 2NH3(g)
For dihydrogen (H2) to become a limiting reagent,
should be
less than .
Here in 56g of N2 + 10g of H2,
Moles of N2 = = 2
and Moles of H2 = = 5
Now by dividing stoichiometric coefficient we get,
For N2 = = 2
For H2 = = 1.67
Here H2 is the limiting reagent.
N2(g) + 3H2(g) 2NH3(g)
For dihydrogen (H2) to become a limiting reagent,
should be
less than .
Here in 56g of N2 + 10g of H2,
Moles of N2 = = 2
and Moles of H2 = = 5
Now by dividing stoichiometric coefficient we get,
For N2 = = 2
For H2 = = 1.67
Here H2 is the limiting reagent.
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