JEE Main 2006 — Some Basic Concepts Of Chemistry Question with Solution
From: AIEEE 2006
Question
How many moles of magnesium phosphate Mg3(PO4)2 will contain 0.25 mole of oxygen atoms?
Choose an option
Show full solutionCorrect option: D
Correct answer
D3.125 10-2
Step-by-step explanation
In one Mg3(PO4)2 molecule no of oxygen atoms = 8
So if there is M mole of Mg3(PO4)2 molecules then no of moles of oxygen atoms is = M 8
According to question,
M 8 = 0.25
M = 0.03125 = 3.125 10-2
So if there is M mole of Mg3(PO4)2 molecules then no of moles of oxygen atoms is = M 8
According to question,
M 8 = 0.25
M = 0.03125 = 3.125 10-2
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This is a previous-year question from JEE Main 2006, covering the Some Basic Concepts Of Chemistry chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.