JEE Main 2021 — Some Basic Concepts Of Chemistry Question with Solution
From: JEE Main 2021 (Online) 24th February Evening Shift
Question
The formula of a gaseous hydrocarbon which requires 6 times of its own volume of O2 for complete oxidation and produces 4 times its own volume of CO2 is CxHy. The value of y is _____________.
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Show full solutionCorrect answer: 8
Correct answer
8
Step-by-step explanation
Combustion reaction :
Suppose, volume of CxHy is V and volume of O2 is 6 times greater than CxHy = 6V
then volume of xCO2 Vx = 4 V
x = 4
Since,
= 6V
..... (i)
Put value of x = 4 in Eq. (i) we get,
Suppose, volume of CxHy is V and volume of O2 is 6 times greater than CxHy = 6V
then volume of xCO2 Vx = 4 V
x = 4
Since,
= 6V
..... (i)
Put value of x = 4 in Eq. (i) we get,
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