JEE Main 2020 — Some Basic Concepts Of Chemistry Question with Solution
From: JEE Main 2020 (Online) 3rd September Evening Slot
Question
6.023 1022 molecules are present in 10 g of a substance 'x'. The molarity of a solution containing
5 g of substance 'x' in 2 L solution is _____ × 10-3
Enter your answer
Show full solutionCorrect answer: 0.025
Correct answer
0.025
Step-by-step explanation
Mass of 6.023 × 1022 molecules of a substance
= 10 g
Mass of 6.023 × 1023 molecules of the substance = 100 g
Molar mass of the substance = 100 g mol–1
Molarity of the solution =
= = 0.025
Mass of 6.023 × 1023 molecules of the substance = 100 g
Molar mass of the substance = 100 g mol–1
Molarity of the solution =
moles of solute
volume of solution(in l)
= = 0.025
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