JEE Main 2014ChemistryStates of MatterEasyMCQ

JEE Main 2014 — States of Matter Question with Solution

JEE Main 2014 (09 Apr Online)

Question

The temperature at which oxygen molecules have the same root mean square speed as helium atoms have at 300 K is : (Atomic masses : He = 4 u, O = 16 u)

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Show full solutionCorrect option: B
Correct answer
B2400 K

Step-by-step explanation

C rms = 3 RT M

C rms He = 3 R × 3 0 0 4 & C rms O 2 = 3 R × T O 2 3 2

∴   ( C rms ) He = ( C rms ) O 2 ⇒   3R×300 4 = 3R× T O 2 32

T O 2 = 3 0 0 × 3 2 4 = 2 4 0 0 K

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About this question

This is a previous-year question from JEE Main 2014, covering the States of Matter chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.