JEE Main 2020ChemistryStates of MatterEasyNumerical

JEE Main 2020 — States of Matter Question with Solution

JEE Main 2020 (06 Sep Shift 1)

Question

A spherical balloon of radius 3 cm containing helium gas has a pressure of 48×10-3 bar. At the same temperature, the pressure, of a spherical balloon of radius12 cm containing the same amount of gas will be………….×10-6 bar.

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Show full solutionCorrect answer: 750
Correct answer
750

Step-by-step explanation

 if volume of 3cm balloon is =V
then volume of 12cm radius balloon =64V
So pressure will become 1 / 64 times =1/64×48×10-3 bar =750×10-3 bar

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About this question

This is a previous-year question from JEE Main 2020, covering the States of Matter chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.