JEE Main 2014 — States of Matter Question with Solution

At very high temperatures & low pressures, the characteristic constant behaviour can be understood from virial expansion

$\text{Z}=\frac{{\text{PV}}_{\text{m}}}{\text{RT}}=1+\left(\text{b}-\frac{\text{a}}{\text{RT}}\right)\frac{1}{{\text{V}}_{\text{m}}}+\frac{{\text{b}}^2}{{\text{V}}_{\text{m}}^2}+\text{....}$

${\mathrm{V}}_{\mathrm{m}}$, molar volume large i.e $\frac{{\text{b}}^2}{{\text{V}}_{\text{m}}^2}\to \text{o}$

i.e Third term in virial expansion can be ignored.

In qualitative terms, the real gas will show ideal behaviour when the intermolecular forces of attraction will be negligible which is possible at high temperature and low pressure.
Also $\left(\text{b}-\frac{\text{a}}{\text{RT}}\right)\to \text{o}$

i.e. $\text{Z}\approx 1$ and gas behaves ideally.