JEE Main 2019 — Structure Of Atom Question with Solution
From: JEE Main 2019 (Online) 10th April Morning Slot
Question
The isoelectronic set of ions is :
Choose an option
Show full solutionCorrect option: C
Correct answer
CN3–, O2-, F- and Na+
Step-by-step explanation
Atomic numbers of N, O, F and Na are 7, 8, 9
and 11 respectively.
Therefore, total number of electrons in each of N3-, O2–, F– and Na+ is 10 and hence they are isoelectronic.
Therefore, total number of electrons in each of N3-, O2–, F– and Na+ is 10 and hence they are isoelectronic.
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This is a previous-year question from JEE Main 2019, covering the Structure Of Atom chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.