JEE Main 2017ChemistryStructure of AtomMediumMCQ

JEE Main 2017 — Structure of Atom Question with Solution

JEE Main 2017 (02 Apr)

Question

The radius of the second Bohr orbit for hydrogen atom is

(Planck's constant, (h)=6.6262×10−34Js; mass of electron =9.1091×10-31kg; charge of electron =1.60210×10-19C; permittivity of vacuum, (∈0)=8.854185×10-12kg-1m-3A2)

Choose an option

Show full solutionCorrect option: C
Correct answer
C2.12 Å

Step-by-step explanation

Radius of the Bohr's orbit is calculated by the following formula rn=0.529×n2zÅ

Radius is directly proportional to square of nth orbit and inversely proportional to atomic number. This formula works for single electron species

here rn=radius of the nth orbit

Z=1 and n=orbit or shell number

r2=0.529×221 Å

=2.12 Å

 

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About this question

This is a previous-year question from JEE Main 2017, covering the Structure of Atom chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.