JEE Main 2019 — Structure Of Atom Question with Solution
From: JEE Main 2019 (Online) 8th April Morning Slot
Question
The quantum number of four electrons are given below :
n = 4, l = 2, ml =–2, ms = –1/2
n = 3, l = 2, ml = 1, ms = +1/2
n = 4, l = 1, ml = 0, ms = +1/2
n = 3, l = 1, ml = 1, ms = –1/2
The correct order of their increasing enegies will be :
n = 4, l = 2, ml =–2, ms = –1/2
n = 3, l = 2, ml = 1, ms = +1/2
n = 4, l = 1, ml = 0, ms = +1/2
n = 3, l = 1, ml = 1, ms = –1/2
The correct order of their increasing enegies will be :
Choose an option
Show full solutionCorrect option: A
Correct answer
AIV < II < III < I
Step-by-step explanation
n = 4, l = 2, 4d orbital, n + l = 6
n = 3, l = 2, 3d orbital, n + l = 5
n = 4, l = 1, 4p orbital, n + l = 5
n = 3, l = 1, 3p orbital, n + l = 4
more is n + l value, more is energy
3p < 3d < 4p < 4d
n = 3, l = 2, 3d orbital, n + l = 5
n = 4, l = 1, 4p orbital, n + l = 5
n = 3, l = 1, 3p orbital, n + l = 4
more is n + l value, more is energy
3p < 3d < 4p < 4d
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This is a previous-year question from JEE Main 2019, covering the Structure Of Atom chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.