JEE Main 2004 — Structure Of Atom Question with Solution
From: AIEEE 2004
Question
The wavelength of the radiation emitted when in a hydrogen atom electron falls from infinity to stationary state 1, would be (Rydberg constant = 1.097 107 m-1)
Choose an option
Show full solutionCorrect option: C
Correct answer
C91 nm
Step-by-step explanation
We know Rydberg formula,
[ for hydrogen atom Z = 1 ]
=
=
= 9.11 10-8 m
= 91.1 10-9 m
= 91.1 nm
[ as 1 nm = 10-9 m ]
[ for hydrogen atom Z = 1 ]
=
=
= 9.11 10-8 m
= 91.1 10-9 m
= 91.1 nm
[ as 1 nm = 10-9 m ]
Practice this on the real CBT interface
Solve this JEE Main question (and the rest of the Structure Of Atom chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.
Solve interactively →About this question
This is a previous-year question from JEE Main 2004, covering the Structure Of Atom chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.