JEE Main 2012 — Structure Of Atom Question with Solution
From: AIEEE 2012
Question
The electrons identified by quantum numbers n and l :
(a) n = 4, = 1
(b) n = 4, = 0
(c) n = 3, = 2
(d) n = 3, = 1
Can be placed in order of increasing energy as :
(a) n = 4, = 1
(b) n = 4, = 0
(c) n = 3, = 2
(d) n = 3, = 1
Can be placed in order of increasing energy as :
Choose an option
Show full solutionCorrect option: B
Correct answer
B(d) < (b) < (c) < (a)
Step-by-step explanation
(a) n = 4, = 1 (p-subshell), so 4p
(b) n = 4, = 0 (s-subshell), so 4s
(c) n = 3, = 2 (d-subshell), so 3d
(d) n = 3, = 1 (p-subshell), so 3p
Accroding to the Bohr ( n + ) rule,
Enery order of the subshell : 3p < 4s < 3d < 4p
Note: When two orbital have the same value of ( n + ) then the orbital which have lower value of n will be filled first.
(b) n = 4, = 0 (s-subshell), so 4s
(c) n = 3, = 2 (d-subshell), so 3d
(d) n = 3, = 1 (p-subshell), so 3p
Accroding to the Bohr ( n + ) rule,
Enery order of the subshell : 3p < 4s < 3d < 4p
Note: When two orbital have the same value of ( n + ) then the orbital which have lower value of n will be filled first.
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This is a previous-year question from JEE Main 2012, covering the Structure Of Atom chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.