JEE Main 2011 — Structure Of Atom Question with Solution
From: AIEEE 2011
Question
A gas absorbs a photon of 355 nm and emits at two wavelengths. If one of the emissions is at
680 nm, the other is at :
Choose an option
Show full solutionCorrect option: B
Correct answer
B743 nm
Step-by-step explanation
Here a photon is divided into two photons of different wavelength.
According to the law of conservation of energy,
Energy of photon before dividing into two parts = Energy of first photon + Energy of second photon
nm = 743 nm
According to the law of conservation of energy,
Energy of photon before dividing into two parts = Energy of first photon + Energy of second photon
nm = 743 nm
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This is a previous-year question from JEE Main 2011, covering the Structure Of Atom chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.