JEE Main 2021ChemistrySurface ChemistryEasyMCQ

JEE Main 2021 — Surface Chemistry Question with Solution

JEE Main 2021 (24 Feb Shift 1)

Question

In Freundlich adsorption isotherm, slope of AB line is:

Choose an option

Show full solutionCorrect option: A
Correct answer
A1n with 1n=0 to 1

Step-by-step explanation

Freundlich adsorption isotherm is :

xm=kp1/n

x= mass of adsorbate
m= mass of adsorbent
P= eq. pressure

k1n=1nlogp+logk
y=mx+c

compairing

m=1n=slope 1n=0 to 1

n>1

logxm=logK+1nlogP

y=c+mx

m=1/n so slope will be equal to 1/n

Hence 0≤1n≤1

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About this question

This is a previous-year question from JEE Main 2021, covering the Surface Chemistry chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.