JEE Main 2017ChemistryThermodynamics (C)MediumMCQ

JEE Main 2017 — Thermodynamics (C) Question with Solution

JEE Main 2017 (09 Apr Online)

Question

A gas undergoes change from state A to state B. In this process, the heat absorbed and work done by the gas is 5 J and 8 J, respectively. Now gas is brought back to A by another process during which 3 J of heat is evolved. In this reverse process of B to A.

Choose an option

Show full solutionCorrect option: B
Correct answer
B6 J of the work will be done by the surroundings on gas

Step-by-step explanation

for A to Bq=5W= −8 J,ΔUAB=dq+dw=5−8ΔUAB=−3



for B to AΔUBA=dq+dwΔUBA= +33=-3 +WBA       WBA=6 J
 

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About this question

This is a previous-year question from JEE Main 2017, covering the Thermodynamics (C) chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.