JEE Main 2022ChemistryThermodynamics (C)MediumNumerical

JEE Main 2022Thermodynamics (C) Question with Solution

JEE Main 2022 (26 Jul Shift 1)

Question

2.4 g coal is burnt in a bomb calorimeter in excess of oxygen at 298 K and 1 atm pressure.

The temperature of the calorimeter rises from 298 K to 300 K. The enthalpy change during the combustion of coal is -x kJ mol-1. The value of x is_____(Given : Heat capacity of bomb calorimeter 20.0 kJK-1. Assume coal to be pure carbon)

Enter your answer

Show full solutionCorrect answer: 200
Correct answer
200

Step-by-step explanation

Cs+O2gCO2g;ΔH=-xkJ/mole

Q=CΔT=20 kJ×2

40 kJ heat is released for 2.4 g of Carbon

For 1 mole 'CarbonQ=402.4×12

=40024×12=200 kJ/mole

Q=ΔE=ΔH=200 kJ Δng=0

x=200

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Thermodynamics (C) chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2022, covering the Thermodynamics (C) chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.