JEE Main 2021ChemistryThermodynamics (C)HardNumerical

JEE Main 2021 — Thermodynamics (C) Question with Solution

JEE Main 2021 (25 Feb Shift 1)

Question

The ionization enthalpy of Na+ formation from Nag is 495.8 kJ mol-1, while the electron gain enthalpy of Br is -325.0 kJ mol-1. Given the lattice enthalpy of NaBr is -728.4 kJ mol -1 . The energy for the formation of NaBr ionic solid is -_____10-1 kJ mol-1

Enter your answer

Show full solutionCorrect answer: 5576
Correct answer
5576

Step-by-step explanation

ΔHformation =IE1+ΔHeg1+LE

=495.8+-325+-728.4

=-557.6

=-5576×10-1KJ/mol .

Note: The above calculation is not for

ΔHformation  but for ΔHReaction 

But on the basis of given data it is the best ans.

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About this question

This is a previous-year question from JEE Main 2021, covering the Thermodynamics (C) chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.