JEE Main 2018ChemistryThermodynamics (C)MediumMCQ

JEE Main 2018 — Thermodynamics (C) Question with Solution

JEE Main 2018 (15 Apr)

Question

An ideal gas undergoes a cyclic process as shown in the figure


∆UBC=-5KJmol-1,qAB=2KJmol-1

WAB=-5KJmol-1,WCA=3KJmol-1 

Heat absorbed by the system during process CA is

Choose an option

Show full solutionCorrect option: B
Correct answer
B+5KJmol-1

Step-by-step explanation

AB→ isobaric

BC→ isochoric

CA→ not defined

For cyclic process, ΔU=0

∆UAB=q+W

=2-5=-3

∆UABC=∆UAB+∆UBC

=-3-5=-8 KJ

∆UCA=+8

=Q+ W

8=Q+3

Q=+5 kJ

Therefore, the heat absorbed by the system during process CA is +5 KJmol−1.

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About this question

This is a previous-year question from JEE Main 2018, covering the Thermodynamics (C) chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.