JEE Main 2017 — Application Of Derivatives Question with Solution
From: JEE Main 2017 (Offline)
Question
The normal to the curve y(x – 2)(x – 3) = x + 6 at the point where the curve intersects the y-axis passes
through the point :
Choose an option
Show full solutionCorrect option: A
Correct answer
A
Step-by-step explanation
Given
At y-axis, x = 0 y = 1
On differentiating, we get
at point (0, 1)
Slope of normal = – 1
Now equation of normal is y – 1 = –1 (x – 0)
y – 1 = – x
x + y = 1 ......(1)
By checking each option you can see point satisfy equation (1).
At y-axis, x = 0 y = 1
On differentiating, we get
at point (0, 1)
Slope of normal = – 1
Now equation of normal is y – 1 = –1 (x – 0)
y – 1 = – x
x + y = 1 ......(1)
By checking each option you can see point satisfy equation (1).
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This is a previous-year question from JEE Main 2017, covering the Application Of Derivatives chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.