JEE Main 2020 — Application Of Derivatives Question with Solution
From: JEE Main 2020 (Online) 5th September Morning Slot
Question
If the point P on the curve, 4x2 + 5y2 = 20 is
farthest from the point Q(0, -4), then PQ2 is equal to:
farthest from the point Q(0, -4), then PQ2 is equal to:
Choose an option
Show full solutionCorrect option: A
Correct answer
A36
Step-by-step explanation
Given ellipse is
Let point P is
(PQ)2 =
(PQ)2 =
(PQ)2 =
=
=
will be maximum when sin = 1
Let point P is
(PQ)2 =
(PQ)2 =
(PQ)2 =
=
=
will be maximum when sin = 1
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