JEE Main 2019MathematicsApplication Of DerivativesTangent And NormaleasyMCQ

JEE Main 2019Application Of Derivatives Question with Solution

From: JEE Main 2019 (Online) 8th April Evening Slot

Question

Given that the slope of the tangent to a curve y = y(x) at any point (x, y) is . If the curve passes through the centre of the circle x2 + y2 – 2x – 2y = 0, then its equation is :

Choose an option

Show full solutionCorrect option: A
Correct answer
Ax loge|y| = 2(x – 1)

Step-by-step explanation

Slope, =



....... (1)

Center of the circle x2 + y2 – 2x – 2y = 0 is (1, 1)

Equation (1) passes through point (1, 1)

0 = -2 + C

C = 2



x

x

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About this question

This is a previous-year question from JEE Main 2019, covering the Application Of Derivatives chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.