JEE Main 2023MathematicsArea Under CurvesHardMCQ

JEE Main 2023Area Under Curves Question with Solution

JEE Main 2023 (29 Jan Shift 1)

Question

Let Δ be the area of the region x,y2:x2+y221,y24x,x1. Then 12Δ-21sin-127 is equal to

Choose an option

Show full solutionCorrect option: D
Correct answer
D3-43

Step-by-step explanation

Plotting the diagram of x2+y221 & y24x for x1 we get,

Now from above diagram required Area Δ=2132xdx+232121-x2dx

Δ=8333-1+21sin-127-63

So, 12Δ-21sin-127

=128333-1+21sin-127-63-21sin-127

=128333-1-63

=23-832

=3-43

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About this question

This is a previous-year question from JEE Main 2023, covering the Area Under Curves chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.