JEE Main 2019MathematicsBinomial TheoremMediumMCQ

JEE Main 2019 — Binomial Theorem Question with Solution

JEE Main 2019 (08 Apr Shift 2)

Question

If the fourth term in the binomial expansion of x11+log10x+x1126 is equal to 200, and x>1, then the value of x is

Choose an option

Show full solutionCorrect option: D
Correct answer
D10

Step-by-step explanation

General term for the given binomial is
Tr+1= 6Crx11+log10x6-rx112r
Given T4=200, putting r=3
⇒T4= 6C3x11+log10x3x1123=200
⇒x11+log10x32⋅x14=10
⇒x321+log10x+14=10
⇒321+log10x+14log10x=1
⇒x=10,10-4
⇒x=10 ( as x>1)

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About this question

This is a previous-year question from JEE Main 2019, covering the Binomial Theorem chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.