JEE Main 2021MathematicsBinomial TheoremProblems Based On Binomial Co Efficient And Collection Of Binomial Co EfficientmediumMCQ

JEE Main 2021Binomial Theorem Question with Solution

From: JEE Main 2021 (Online) 24th February Morning Shift

Question

The value of
-15C1 + 2.15C2 – 3.15C3 + ... - 15.15C15 + 14C1 + 14C3 + 14C5 + ...+ 14C11 is :

Choose an option

Show full solutionCorrect option: D
Correct answer
D213 - 14

Step-by-step explanation













We know,

214 - 1

213

Also let, S = 14C1 + 14C3 + 14C5 + ...+ 14C11

S + 14C13 = 14C1 + 14C3 + 14C5 + ...+ 14C11 + 14C13

S + 14C13 = 213

S + 14 = 213

S = 213 - 14

Other Method :

We know,

Differentiating both sides with respect to x,



Put



We know,

214 - 1

213

Also let, S = 14C1 + 14C3 + 14C5 + ...+ 14C11

S + 14C13 = 14C1 + 14C3 + 14C5 + ...+ 14C11 + 14C13

S + 14C13 = 213

S + 14 = 213

S = 213 - 14

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About this question

This is a previous-year question from JEE Main 2021, covering the Binomial Theorem chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.