JEE Main 2021 — Binomial Theorem Question with Solution
From: JEE Main 2021 (Online) 17th March Evening Shift
Question
The value of is equal to :
Choose an option
Show full solutionCorrect option: A
Correct answer
A924
Step-by-step explanation
Given,
=
Now,
\eqalign{ & = \left( {{}^6{C_0} + {}^6{C_1}x + {}^6{C_2}{x^2} + ... + {}^6{C_6}{x^6}} \right) \cr & \left( {{}^6{C_0} + {}^6{C_1}x + {}^6{C_2}{x^2} + ... + {}^6{C_6}{x^6}} \right) \cr}
Comparing coefficient of x6 both sides
= = 924
=
Now,
\eqalign{ & = \left( {{}^6{C_0} + {}^6{C_1}x + {}^6{C_2}{x^2} + ... + {}^6{C_6}{x^6}} \right) \cr & \left( {{}^6{C_0} + {}^6{C_1}x + {}^6{C_2}{x^2} + ... + {}^6{C_6}{x^6}} \right) \cr}
Comparing coefficient of x6 both sides
= = 924
Practice this on the real CBT interface
Solve this JEE Main question (and the rest of the Binomial Theorem chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.
Solve interactively →About this question
This is a previous-year question from JEE Main 2021, covering the Binomial Theorem chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.